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To Admin - This is not my homework, My teacher solved it but I am trying to solve this problem using other methods. If I posted this in wrong group, please message me and I will Post this in correct corner.

Problem - To find acceleration in both blocks sliding on smooth surface,string and pulley is frictionless and massless. Refer to diagram below.Use g = 9.8 m/s2

My Solution -

Free Body Diagram Of Block of mass M kg -

The Equation of forces in Y axis is

9.8M - Tsinα = Macosα .......eq(1)

The Equation of forces in X axis is

Tcosα = MAsinα ...........eq(2)

Free Body Diagra of Block of Mass N kg -

The Equation of forces in Y axis is

Tsinβ - 9.8N = Nasinβ .........eq(3)

The Equation of forces in X axis is

Tcosβ = Na.cosβ ..........eq(4)

Now, after simultaneously solving eq(1) and eq(3), I am getting wrong answer

Now, eq(4) is tell that T = Na which is not possible.

Problem - To find acceleration in both blocks sliding on smooth surface,string and pulley is frictionless and massless. Refer to diagram below.Use g = 9.8 m/s2

My Solution -

Free Body Diagram Of Block of mass M kg -

The Equation of forces in Y axis is

9.8M - Tsinα = Macosα .......eq(1)

The Equation of forces in X axis is

Tcosα = MAsinα ...........eq(2)

Free Body Diagra of Block of Mass N kg -

The Equation of forces in Y axis is

Tsinβ - 9.8N = Nasinβ .........eq(3)

The Equation of forces in X axis is

Tcosβ = Na.cosβ ..........eq(4)

Now, after simultaneously solving eq(1) and eq(3), I am getting wrong answer

Now, eq(4) is tell that T = Na which is not possible.

__I guess I missed Normal Reaction Force but how to use it in equation__